Budapest

Gregory S Kaidanov ()

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1989
1/2 : 1/2

Paul Van der Sterren (2500)

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1.c4 e6 2.Nc3 d5 3.d4 Nf6 4.Nf3 Be7 5.Bf4 O-O 6.e3 c5 7.dxc5 Bxc5 8.Be2 dxc4 9.Bxc4 a6 10.O-O b5 11.Bd3 Bb7 12.Qe2 Nbd7 13.Rfd1 Qe7 14.Bg5 h6 15.Bh4 Qe8 16.Rac1 Be7 17.Bb1 Rc8 18.a3 Nc5 19.Ne5 Nd5 20.Qc2 g6 21.Bxe7