Corr

Peter Kruchem ()

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1991
1 : 0

E. Padberg ()

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1.e4 c5 2.Nf3 e6 3.d4 cxd4 4.Nxd4 a6 5.Nc3 Nc6 6.g3 Nge7 7.Bg2 Nxd4 8.Qxd4 Nc6 9.Qe3 d6 10.O-O Be7 11.b3 O-O 12.Bb2 Bf6 13.Rfd1 Qc7 14.f4 b5