Corr

W. Schneider ()

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1986
0 : 1

Mathias Pohl ()

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1.d4 d5 2.e4 dxe4 3.Nc3 Nf6 4.f3 exf3 5.Nxf3 g6 6.Bc4 Bg7 7.O-O O-O 8.Qe1 Nc6 9.Qh4 Bg4 10.Be3 Bxf3 11.Rxf3 e6 12.Ne2 Nd5