FSGM Oktober

Peter Lukacs (2485)

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1993.10
1/2 : 1/2

D. Avrukh (2440)

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1.d4 Nf6 2.c4 g6 3.Nc3 Bg7 4.e4 d6 5.Nf3 O-O 6.Be2 e5 7.O-O Nc6 8.Be3 Ng4 9.Bg5 f6 10.Bc1 f5 11.Bg5 Qe8 12.exf5 gxf5 13.dxe5 dxe5 14.h3