SWE Ch

Lennart Liljedahl (2315)

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1973
1/2 : 1/2

Bengt Ekenberg ()

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1.b3 e5 2.Bb2 Nc6 3.c4 Nf6 4.Nc3 d5 5.cxd5 Nxd5 6.Nf3 Nxc3 7.Bxc3 Bd6 8.Qc2 O-O 9.g3 Qe7 10.Bg2 f6 11.O-O Nb4 12.Qb1 c6 13.e4